Question

From a rifle of mass 4 kg , a bullet of mass 50 g fired with an initial velocity of 35 m/s . Calculatate the initial recoil velocity of the rifle.​

Answer 1

Answer:

Here ,

$mass \: of \: bullet = 50g$

$= \frac{50}{1000} kg$

$= 0.05kg$

$initial \: velocity \: of \: the \: bullet = 35 \: m {s}^{ - 1}$

now,

$momenturm \: of \: the \: bullet = \: m \times v$

$= 0.05 \times 35$

$= 1.75 \: kg \: m {s}^{ - 1}$

Again,

$mass \: of \: the \: rifle = 4kg$

Let, the recoil velocity of the rifle is v m/s

Therefore,

$momentum \: of \: the \: rifle = 4 \: kg \times v \: m {s}^{ - 1}$

$= 4v \: kg \: m {s}^{ - 1}$

Now, according to the law of conservation of momentum.

Momentum of the bullet = momentum of the rifle.

$= > 1.75 = 4v$

$= > \: v = \frac{1.75}{4}$

$= > v = 0.4375$

$= > v = 0.438 \: m {s}^{ - 1}$

Thus, the recoil velocity of the rifle is 0.438 m/s

Answer 2

Answer:

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