Question

from a rifle of mass 4 kg A bullet of mass 50 gram is fired horizontally with an initial velocity of 40 ms-¹ calculate the initial recoil velocity of the rifle​

Answer 1

M = 4 kg              m  = 50 gms

v  = 35 m/sec

initial momentum of rifle and bullet together = 0.  So  as per the conservation of linear momentum,

      0 = M * (-V) +  m  v  

=>     0   = 4 * (-V) + 50/1000  * 35

 

V =  0.4375  m/sec    recoil velocity

Answer 2

Hello mate

Ur answer :

M = 4 kg          

m  = 50 gms

v  = 35 m/sec

initial momentum of rifle and bullet together = 0.  

So  as per the conservation of linear momentum,

      0 = M * (-V) +  m  v  

=>     0   = 4 * (-V) + 50/1000 * 35

 

V =  0.4375  m/sec  recoil velocity

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