Question

From a rifle of mass 8 kg, a bullet of mass 25 g is fired with an initial velocity of 50 m/s. Calculate the initial recoil velocity of the rifle.

Answer 1

Answer:

velocity of the gun= 0.156m/s

Explanation:

by the law of conservation of momentum,

• momentum before firing=momentum after firing
• 0= M(gun)×V(gun) + M(bullet)×V(bullet)
• M(gun)×V(gun)= - {M(bullet)×V(bullet)}
• V(gun)= -{M(bullet)×V(bullet)}÷M(gun)

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$v(gun) = \frac{25 \times {10}^{ - 3} \times 50 }{8} \\ = \frac{1250 \times {10}^{ - 3} }{8} \\ = .156$

(-ve indicates that velocity of the gun is in the opposite direction of bullet)

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hope it helps...!!!

Answer 2

I don't know

I don't know