Question

From a rope 11 m long. Two pieces of length 1 3/5 m  and 3 3/10 m are cut of. What is the length of the remaining rope?

Answer 1

Remaining rope : 11m - 1 3/5m - 3 3/10m =
110/10 - 16/10 - 33/10 = 110/10 - 49/10
= 61/10 m
= 6 1/10 m

Answer 2

total length of rope = 11m
lengths of the pieces that were cut are $1 \frac{3}{5}m = \frac{8}{5}m$ and $3 \frac{3}{10}m = \frac{33}{10}m$

length of cut pieces = $\frac{8}{5} + \frac{33}{10} = \frac{8*2+33}{10} = \frac{16+33}{10} = \frac{49}{10} m$

Length of remaining rope = $11- \frac{49}{10} = \frac{11*10-49}{10} = \frac{110-49}{10} = \frac{61}{10} m$