Math, asked by daresing62, 1 month ago

from a rope 11m long tow pieces of lengths 2 3/5 m and 3 3/10 m are cut off.what is the lenght of remaining rope​

Answers

Answered by EvilRage
0

Answer:

8.1 m

Step-by-step explanation:

Total length of rope = 11m

Length of first piece = 2 3/5 = 13/5m

Length of second piece = 3/10m

Length of first piece + length of second piece = 13/5+3/10

= 26/10+3/10

= 29/10

= 2.9m

Remaining rope = 11-2.9 = 8.1m

Answered by bookworm2008
0

Answer:

5 1/10

Step-by-step explanation:

2 3/5 + 3 3/10 = 59 / 10

11 - 59 / 10 = 51 / 10 = 5 1/10

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