From a rope 11m long, two pieces of length 2 3/5 m and 3 3/10 m are cut off. what is the length of the remaining rope??? ( 2 3/5 it is mixed fraction)
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sum of two pieces which are cut off =6/5+33/10=>12+33/10(l.c.m of 5 and 10 is 10)
=>45/10=4.5 m
Remaining length => 11m -4.5m =>6.5m
The remaining length is 6.5m
=>45/10=4.5 m
Remaining length => 11m -4.5m =>6.5m
The remaining length is 6.5m
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