from a rope 11m long ,
two pieces of lengths 13/5 m and 33/10 m are cut off what is the length of the remainning rope ?
Answers
Answered by
52
Heya !!!
Let the Length of remaining rope be X m.
Sum of Length of two pieces of rope = 13/5 + 33/10
=> 26 + 33/10 = 59/10 m
Total length of rope = 11 m
Therefore,
59/10 + X = 11
59 + 10X/10 = 11
59 + 10X = 110
10X = 110-59
10X = 51
X= 51/10
Hence,
the length of remaining rope is 51/10 m
HOPE IT WILL HELP YOU...... :-)
Let the Length of remaining rope be X m.
Sum of Length of two pieces of rope = 13/5 + 33/10
=> 26 + 33/10 = 59/10 m
Total length of rope = 11 m
Therefore,
59/10 + X = 11
59 + 10X/10 = 11
59 + 10X = 110
10X = 110-59
10X = 51
X= 51/10
Hence,
the length of remaining rope is 51/10 m
HOPE IT WILL HELP YOU...... :-)
Answered by
33
Heya
Here's your answer ↓
Total length of rope = 11 m
First piece = 13/5
Second piece = 33/10
Total length of cut off rope
= 13/5 + 33/10
= 13 × 2 / 5 × 2 + 33/10
= 26/10 + 33/10
= 59/10
Remaining Length of the rope
= 59/10 - 11/1
= 59 / 10 - 11 × 1 / 1 × 10
= 59 / 10 - 11 / 10
= 51 / 10 m
Hence, the length of the remaining rope is 51/10 m
Hope this helps you ☺️☺️☺️
Here's your answer ↓
Total length of rope = 11 m
First piece = 13/5
Second piece = 33/10
Total length of cut off rope
= 13/5 + 33/10
= 13 × 2 / 5 × 2 + 33/10
= 26/10 + 33/10
= 59/10
Remaining Length of the rope
= 59/10 - 11/1
= 59 / 10 - 11 × 1 / 1 × 10
= 59 / 10 - 11 / 10
= 51 / 10 m
Hence, the length of the remaining rope is 51/10 m
Hope this helps you ☺️☺️☺️
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