Math, asked by mehak104, 1 year ago

from a rope 11m long ,
two pieces of lengths 13/5 m and 33/10 m are cut off what is the length of the remainning rope ?

Answers

Answered by Panzer786
52
Heya !!!


Let the Length of remaining rope be X m.




Sum of Length of two pieces of rope = 13/5 + 33/10


=> 26 + 33/10 = 59/10 m


Total length of rope = 11 m



Therefore,


59/10 + X = 11



59 + 10X/10 = 11


59 + 10X = 110

10X = 110-59



10X = 51


X= 51/10


Hence,

the length of remaining rope is 51/10 m



HOPE IT WILL HELP YOU...... :-)
Answered by PrincessNumera
33
Heya 


Here's your answer ↓


Total length of rope = 11 m 

First piece = 13/5

Second piece = 33/10




Total length of cut off rope

 = 13/5 + 33/10

= 13 × 2 / 5 × 2 + 33/10 

= 26/10 + 33/10 

= 59/10




Remaining Length of the rope 

= 59/10 - 11/1

= 59 / 10 - 11 × 1 / 1 × 10

= 59 / 10 - 11 / 10

= 51 / 10 m 


Hence, the length of the remaining rope is 51/10 m 


Hope this helps you ☺️☺️☺️
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