Math, asked by dona6677, 2 months ago

From a set of 100 cards numbered 1 to 100, one card is drawn at random. The probability that the number obtained on the card is divisible by 6 or 8 but not by 24, is​

Answers

Answered by vipinkumar212003
1

Step-by-step explanation:

\blue{\mathfrak{\large{Total \: number \: of \: cards =100}}} \\ \blue{\mathfrak{\large{Number \: of \: cards \: divisible \: by \: 6 \: or \: 8 \: but \: not \: by24}}} \\ \blue{\mathfrak{\large{ =Number \: of \: cards \: divisible \: by \: 6 \: but \: not \: by \: 24 }}} \\ \blue{\mathfrak{\large  { + Number \: of \: cards \: divisible \: by \: 8 \: but \: not \: by \: 24}}} \\ \blue{\mathfrak{\large{ = 12 + 8}}} \\ \blue{\mathfrak{\large{ = 20}}} \\ \blue{\mathfrak{\underline{\large{Probability \: of \: getting \: number \: divisible \: by \: 6 \: or \: 8 \: but \: not \: by \: 24}}}:} \\ \blue{\mathfrak{\large{ =  \frac{Number \: of \: cards \: divisible \: by \: 6 \: or \: 8bt \: not \: by24}{Total \: number \: of \: cards} }}} \\ \blue{\mathfrak{\large{ =  \frac{20}{100} }}} \\ \blue{\mathfrak{\large{ =  \frac{1}{5} }}} \\  \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}

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