from a solid cylinder of h=40 cm and d=18 cm , a conical cavity of same height and same diameter are hollowed out. Find TSA of remaining solid
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Answer:3419.46
Step-by-step explanation: TSA of solid = CSA of cylinder + CSA of cone
=2πrh + πrl
=πr( 2h+l )
=3.14×9 [2(40)+41]
=28.26×121
=3419.46 cm
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