Question

From a solid cylinder of height 14 cm and base diameter 7 cm, two equal conical holes each of radius 2.1 cm and height 4 cm are cut off. Find the volume of the remaining solid. ​

Answer 1

Given:-

Height of cylinder = 14 cm

Diameter of base = 7 cm

To Find:-

The volume of the remaining solid.

Solution:-

We know,

Volume of cylinder = πr²h

= $\frac{22}{7}$ × $\frac{7}{2}$ × $\frac{7}{2}$ × 14

= 11 × 7 × 7

= 539

Now,

Radius of cone = 2.1 cm ( GIVEN )

Height = 4 cm ( GIVEN )

Volume of 2 cones = 2 × $\frac{1}{3}$ πr²h

= 2 × $\frac{1}{3}$ × $\frac{22}{7}$ × 2.1 × 2.1 × 4

= 44 × 0.1 × 2.1 × 4

= 36.96

Volume of remaining solid is 539 – 36.96 = 502.04

$\bf The \: volume \: of \: the \: remaining \: solid \: is \: 502.04 \: cubic \: cm \: [Ans]$

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