from a solid cylinder of height 14 cm and best time base diameter 7 cm to equal conical holes each of radius 2.1 cm and height 4 cm hollowed out find the volume of remaining solid
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Answer:
Step-by-step explanation:
Diameter 7cm radius = 3.5cm
Volume of cylinder = πr^2h
22/7× 3.5×3.5×14
= 539 cm^3
Volume of two cone = 1/3πr^h
1/3×22/7×2.1×2.1×4
18.48 cm^3
Remaining solid = 539-18.48
=520.52
mahek57:
Thank you
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