From a solid cylinder of height 14cm and base diameter 7cm , two equal conical holes each of radius 2.1cm and height 4cm are cut off . Find the volume of the remaining solid.
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Answer:
Volume of cylinder= π×r×r×h
=22/7×3.5×3.5×14
=539 sqcm
Volume of conical holes=1/3π×r×r×h
=1/3×22/7×2.1×2.1×4
=18.48 sqcm
There are two conical holes so
2×18.48
=36.96 sqcm
So remaining volume= 539 - 36.96
=502.04 sqcm
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