Question

from a solid cylinder of height 16 cms and radius is 12cms

Answer 1

bhi kam se kam questions to complete kar

Answer 2

Sol:
Radius of the cylinder = 6 cm
Height of the cylinder = 8 cm

Volume of the solid cylinder = πr2h
= 22/7 × 6 × 6 × 8
= 905.14 cm2

Radius of the base of the conical cavity = 6 cm
Height of the conical cavity = 8 cm

Volume of the conical cavity = 1/3 πr2h
= 1/3 × 22/7 × 6 × 6 × 8
= 301.71 cm2

Volume of the remaining solid = 905.14 - 301.71
= 603.43 cm2

Total surface area of the remaining solid = CSA of the cylinder + CSA of the conical cavity + Area of the base of the cylinder

CSA of the cylinder = 2πrh = 2π × 6 x 8 = 96 π

CSA of the conical cavity = πrl = πr√[(r)2 + (h)2]
= π x (6)2 x √[(6)2 + (8)2]
= π x (6)2 x √100
= π x 36 x 10
= 360 π
Area of the base of the cylinder = π r2 = π (6)2 = 36 π

Total surface area of the remaining solid = 96 π + 360 π + 36 π = 492 π = 492 x 3.1412 = 1545.4704 cm2