From a solid cylinder whose height is 16 cm and radius is 12 cm ,a conical cavity of heiht 8cm and of base radius 6 cm is hollowed out find the volume and total surface area of remaining solid
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Answer:
9353.14 cm³=volume remaining
remainig total surface area= 905.14
Step-by-step explanation:
volume of cylinder = πr²h
=22/7*12*12*16=67584/7 cm³
volume of cone= 1/3πr²h
=1/3*22/7*6*6*8 =2112/7 cm³
remaining volume = volume of cylinder -volume of cone
67584/7-2112/7 =65472/7 = 9353.14 cm³
surface area
surface area of cylinder = 2πrh
=2*22/7*12*16 = 8448/7 cm²
surface area of cone = πr(l+r)
=22/7*6*16 ( l=√r²+h².)
=2112/7 cm²
rmaining surface area =8448/7-2112/7
=6336/7=905.14 cm²
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