the driver of a train a running and 25 m per second sights a train be moving in the same direction on the same track with 15 M per second the driver of train a applies break to produce a deceleration of 1 M per second square what should be the minimum distance between a trains to avoid accident
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Answered by
78
The relative speed between the two trains is :
25 - 15 = 10m/s
This is the initial relative speed.
When brakes are applied the train slows down.
Given the acceleration = 1 m/s²
u = 10 m/s
With time the train comes to a sudden stop making the velocity 0.
V² = U² - 2as
0 = 100 - 2s
100 = 2s
S = 100/2
S = 50m
= 50m
Answered by
15
Answer:The relative speed between the two trains is :
25 - 15 = 10m/s
This is the initial relative speed.
When brakes are applied the train slows down.
Given the acceleration = 1 m/s²
u = 10 m/s
With time the train comes to a sudden stop making the velocity 0.
V² = U² - 2as
0 = 100 - 2s
100 = 2s
S = 100/2
S = 50m
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Explanation:
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