Question

from a solid cylinder whose sides are 2.4 cm and diameter 1.4cm a conical cavity of the same height and same diameter in hollowed out . find the total surface area of the remaining solid to the nearest cm2




​

Answer 1

Step-by-step explanation:

Hope it will help you..

.

.

.

Follow for more answers and please mark it as brainliest

Answer 2

Step-by-step explanation:

Let 'r' be the radius and 'h' be the height of the cylinder, then

Radius (r) = 0.7 cm

Height (h)= 2.4 cm

Let r1 cm be the radius, l cm be the slant height and h1 cm be the height of the cone, then r1 = 0.7 cm and h1 = 2.4 cm

Now, l = √r1² + h1²

=====> √(0.7)² + (2.4)²

=====> √6.25

=====> 2.5cm

Now,

Total surface area of the remaining solid = (C.S.A of cylinder) + (C.S.A of the cone) + (area of upper base of the cylinder)

===> 2πrh + πr²l + πr²

===> 2πrh + πrl + πr² ( r = r1 )

===> (2×22/7×0.7×2.4 + 22/7×0.7×0.7×2.5 + 22/7×0.7×0.7)

===> 1.56+5.5+1.54

===> 17.6 cm².

Hence, the area of the remaining solid surface = 17.6 cm² = 18 cm².