Question

from a solid right circular cylinder of height 14 cm and base radius 6 CM a right circular cone of the same height and same base radius is removed find the volume of the remaining solid

Answer 1

YOUR ANSWER IS 528 cm³.

PREVIOUS KNOWLEDGE:-

Volume of a right circular cylinder =

$\pi \: r {}^{2} h$

Volume of a right circular cone =

$1 \div 3\pi \: r {}^{2} h$

EXPLANATION:-

Given-

Height of the right circular cylider (h) = 14cm.

Base of radius of cylinder = 6cm.

Now, according to the question a cone is removed of same height and same radius.

Therefore volume the remaining solid =

Volume of the cylinder - Volume of the cone which is removed.

Now see the attachment for further procedure.

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Answer 2

Volume of remaining solid=1056 cubic cm

Step-by-step explanation:

Height of cylinder=h=14 cm

Radius of cylinder=r=6 cm

Height of cone=Height of cylinder=h=14 cm

Radius of cone=r=6 cm

Volume of cylinder=$\pi r^2 h$

Volume of cone=$\frac{1}{3}\pi r^2 h$

Volume of remaining solid=Volume of cylinder-volume of cone=$\pi r^2 h-\frac{1}{3}\pi r^2 h=\frac{2}{3}\pi r^2 h$

Where $\pi=\frac{22}{7}$

Volume of remaining solid=$\frac{2}{3}\times \frac{22}{7}\times (6)^2\times 14=1056cm^3$

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