From a solution containing milk and water in the ratio 3 : 4, 10 l is removed andreplaced by water. If the resultant solution contains milk and water in the ratio 1 : 2then what was the amount of the original solution ?From a solution containing milk and water in the ratio 3 : 4, 10 l is removed andreplaced by water. If the resultant solution contains milk and water in the ratio 1 : 2then what was the amount of the original solution ?
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Original quantity of Milk : Water = 3:4
Therefore,
Original quantity of milk = 3x
Original quantity of water = 4x
Given, 10 l milk is removed from Solution and it is replaced by 10 l water.
Therefore,
New quantity of milk = 3x - 10
New quantity of water = 4x + 10
New Ratio = 1:2
Therefore...
(3x - 10)/(4x + 10) = 1/2
2(3x - 10) = 4x + 10
6x - 20 = 4x + 10
6x - 4x = 10 + 20
2x = 30
x = 15
x = 15; So Original quantity of milk = 3x = 3(15) = 45
x = 15; So Original quantity of water = 4x = 4*15 = 60
Therefore,
Original quantity of milk = 3x
Original quantity of water = 4x
Given, 10 l milk is removed from Solution and it is replaced by 10 l water.
Therefore,
New quantity of milk = 3x - 10
New quantity of water = 4x + 10
New Ratio = 1:2
Therefore...
(3x - 10)/(4x + 10) = 1/2
2(3x - 10) = 4x + 10
6x - 20 = 4x + 10
6x - 4x = 10 + 20
2x = 30
x = 15
x = 15; So Original quantity of milk = 3x = 3(15) = 45
x = 15; So Original quantity of water = 4x = 4*15 = 60
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