From a sphere of radius 1 m, a sphere of radius 0.5 m is removed from the edge. The shift in cente of mass is
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since density of materials of original sphere and removed portion is same so
(mass of original sphere)/(volume of original sphere)
= (mass of removed sphere)/(its volume)
volume of sphere =(4/3)× 3.14 × (radius)^3
(mass of original sphere)/(volume of original sphere)
= (mass of removed sphere)/(its volume)
volume of sphere =(4/3)× 3.14 × (radius)^3
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