from a top of 50m high tower the angle of depression of top and bottom of a pole are observed to be 60⁰ and 45⁰ respectively find the height of the pole
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Step-by-step explanation:
In the fig CE is the height of the pole and x be the distance between tower and pole.
In ∆ADE
tan 45° =
1 =
x = 50-h ----- (1)
In ∆ABC
tan 60° =
√3 =
x =
-----(2)
On substituting value of x in eqn (1), we get
50 – h =
h = 50 -
⇒
⇒ 21.13m
Therefore the height of the pole is 21.13m
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Answer:
heigjt of pole is 22.13 m
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