Question

x2-4ax-4b2+4a2=0
answer the above equation
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Answer 1

Answer:

^2-4ax+4a^2-b^2=0x^2-2*2a*x+(2a)^2-(b)^2 =0(x-2a)^2-(b)^2=0(x-2a-b)(x-2a+b)=0x-2a-b=0 x-2a+b=0x=b+ 2a x=2a-bTherefore, x= 2a+b or 2a-b.