Question

From a top of a 7m high building, the angle of elevation of the top of a cable tower is 60 degree and the angle of depression of its foot is 45 degree. Determine the height of the tower.

PLZ ANSWER IN UNDERROOTS and WITH THE FIGURE.

Answer 1

Let BD = 7 is height of the building and AE is the height of the tower.

From the figure BD = CE = 7

Now from Δ BED

tan 45 = BD/DE

=> 1 = 7/DE

=> DE =7

Now DE = BC = 7

Again in Δ ABC

tan 60 = AC/BC

=> √3 = AC/7

=> AC = 7√3

The height of the tower = AE = AC + CE

= 7√3 + 7

= 7(√3 + 1) m

So height of the tower is 7(√3 + 1) m

Answer 2

U can calculate the whole sum by using trigonometry identities.