Question

From a tower of height 20 m a boy throws a stone in the vertically upward direction with a velocity of 40 m/s and at the same time a girl drops another identical stone from the same tower. When the momentum of the stone dropped by the girl is maximum what will be displacement of the stone projected in the upward direction from the top of the tower? (Take acceleration due to gravity of earth as 10 m/s^2)

Answer 1

The momentum of the stone dropped by the girl is maximum when the stone strikes the ground .

In this case , u=0 , s=20m , a=10m/s^2 ,t=?

by formula

s=ut + 1/2at²

20 =0+ 1/2(10)t²

20=5t²

t²=4

t=2sec (time is always +ve)

Now the displacement of stone thrown upward

In this case u=40m/s , t=2sec , a=-10m/s²

h=40×2 + 1/2(-10)(2)²

h=80 -20

h=60m

Answer 2

60 m

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