From a tower of height h, a particle is thrown vertically upwards with speed.time taken by particle to hit ground,is n times that taken by it to reach the highest point.find relation between h,u,n
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As H is the height of tower
time taken by particle to reach highest point of its path is t=u/g
so speed on reaching ground,v=2+2gH>^2
now v=u + at
=>v= -u + gt’
=>2+2gH>^2= -u + gt[from above]
on solving
t’=[u+2+2gH>^2]/g
given that time taken by particle to hit ground is n times that taken by it to reach the highest point.
=>t’=[u+2+2gH>^2]/g =nu/g
on solving
2gH=n[n-2]u2
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