Question

From a town P, buses start at regular interval of 20 s and run towards town Q with a
constant speed of 50 km/h. At some point of time, all the buses simultaneously have
to reduce their speeds to 40 km/h for some reason. The time interval between the
arrivals of the buses at town Q now will be?​

Answer 1

The time interval will be 25 sec

Explanation:

As it is given in the question that the speed of the buses reduced due to some reason by 4/5 of the original speed so the time will increase 5/4 times which is 25 sec.

Another way to find this, as the velocity is uniform so,

(50)(20) = (t) (40)

t = 25 sec

Answer 2

Answer:

25 sec

Explanation:

From a town P, buses start at regular interval of 20 s and run towards town Q with a constant speed of 50 km/h

=> Distance between two buses = 50 *  20/3600 km

= 5/ 18 km

Now Speed reduced to 40 km/Hr

So time taken to cover 5/18  km distance

= (5/18) /40  hr

= 1/(18 * 8) hr

= 3600/ ( 18 * 8) secs

= 200/8

= 25 sec

The time interval between the arrivals of the buses at town Q now will be

= 25 sec