Question

From a well shuffled deck of cards, all cards which are multiple of 3 are removed along
with all clubs and even numbered, red cards. What is the probability of picking a card
with odd number from the deck?

Answer 1

Answer:

if (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x : yif (5x + 2y) : (7x + 4y) = 13 : 20 find x :

Step-by-step explanation: