Question

from a well shuffled pack of playing cards , black kings , black jacks , black aces are removed .

A card is then drawn at a random from a pack .Find the probability of getting

1. a red card

2. not a diamond card

Answer 1

Answer:

i)Probability = $\frac{13}{23}$

ii) Probability = $\frac{33}{46}$

Step-by-step explanation:

Total Number of cards in deck = 52

Total black Kings =2

Total black Jacks=2

Total black aces = 2

Remaining cards after removal = 52 -6

                                                    =46

total number of outcomes = 46

i) total number of red cards in deck = 13 diamond + 13 hearts

                                                           = 26 cards

Probability of of finding red card = $\frac{26}{46}$

                                                       = $\frac{13}{23}$

ii) Total number of diamond cards = 13

cards which are not diamond = 46- 13

                                                  =33

which is the favor able outcome

Probability = $\frac{33}{46}$

Answer 2

Answer:

(1) 13/23 (2) 33/46

Step-by-step explanation:

Total number of cards in a deck = 52

Total number of cards removed = 2 + 2 + 2 = 6 black cards

Total number of cards left = 52 - 6 = 46

Find the probability of getting a red card:

Number of red card = 26

P(red card) = 26/46 = 13/23

Find the probability that it is not a diamond card:

Number of diamond card = 13

P(diamond card) = 13/46

P(not a diamond card) = 1 - 13/46 = 33/46

Answer: (1) 13/23 (2) 33/46