Question

From an elevated point 'P' a stone is projected vertically upwards, when it reaches a distance 'd' below 'p',

its velocity is doubled. The greatest height reached by it above 'P' is )

$(1)d \div 3$
(2)2d
(3)3d
(4)d÷2




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Answer 1

Answer:

vdffshlgzjfsbvfskzujcst fyimg. tikm

Answer 2

Answer:

v-u=at

2 v=u

doubled:2u -u =at

2u^2-u^2 =2as

d=3u^2÷2a

h=u^2÷2g

= d÷3