Question

from an external point p, tangents PA and PB are drawn to a circle with centre O. If CD is the tangent to a point E PA = 14 find the perimeter of triangle PCD

Answer 1

Answer:

AC=CE , ED=BD &AP=PB(tangents from the same external point are equal)

AC=CE=PA-PC=14-PC

ED=BD=PB-PD=14-PD

Perimeter of ∆PCD=PC+CD+DP

=PC+CE+ED+PD

=PC+(14-PC)+(14-PD)+PD

=14+14

=28cm

Answer 2

Hope it helps .

PA =PB=14