from apack of 52plauing cards Jack King or queen King and ace of red colour are removed from the remaining a card drawn at randomfi d probablit
Answers
Step-by-step explanation:
Total no. of cards in a pack =52
After removing red-colored - jack, queen, king, and aces,
No. of cards =52−8=44 and
No. of red cards =26−8=18.
Solution(i):
No. of black queens =2
Therefore,
2
C
1
( Selecting 1 out of 2 items) times out of
44
C
1
( Selecting 1 out of 44 items) a black queen is picked.
Let E be the event of getting a black queen from pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
44
C
1
2
C
1
=
44
2
=
22
1
Solution(ii):
No. of red cards =18
Therefore,
18
C
1
( Selecting 1 out of 18 items) times out of
44
C
1
( Selecting 1 out of 44 items) a red card is picked.
Let E be the event of getting a red card from the pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
44
C
1
18
C
1
=
44
18
=
22
9
Solution(iii):
No. of black jack cards =2
Therefore,
2
C
1
( Selecting 1 out of 2 items) times out of
44
C
1
( Selecting 1 out of 44 items) a black jack card is picked.
Let E be the event of getting a black jack card from the pack
We know that, Probability P(E) =
(Total no.of possible outcomes)
(No.of favorable outcomes)
=
44
C
1
2
C
1
=
44
2
=
22
1