From diagram, A copper ring is suspended by a thread in a vertical plane. One end of a magnet is brought horizontally towards the ring then the position of the ring will be affected by
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- The magnetic flux is given by
ϕ=BAcosθ
where θis angle between magnetic field and area of ring.
- In this case the area vector is out of the plane, hence
θ=90 ;⇒ϕ=0
The ring will not move from the magnet, as there is no change in flux through ring and current in it will be zero. Ring will not behave as a magnet.
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