from each end of a solid metal cylinder metal was scoop out in hemispherical form of same diameter . the height of the cylinder is 10 cm and its base is of radius 4.2 cm . the rest of cylinder is melted and converted into cylindrical wire of 4.2 cm thickness . find the length of the wire
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let the 2 hemispheres scooped out form a sphere of radius=4.2
therefore volume removed from cylinder=volume of sphere=(4π(4.2)^3)/3 =98.784π cm^3
volume of cylinder after removal=176.4π-98.784π=77.616π cm^3
this volume gets converted into new cylinder of diameter=4.2cm
therefore radius=2.1cm
volume of new wire=4.41πhcm^3
where h is required height
now
4.41πh=77.616π
therefore h=17.6cm
therefore volume removed from cylinder=volume of sphere=(4π(4.2)^3)/3 =98.784π cm^3
volume of cylinder after removal=176.4π-98.784π=77.616π cm^3
this volume gets converted into new cylinder of diameter=4.2cm
therefore radius=2.1cm
volume of new wire=4.41πhcm^3
where h is required height
now
4.41πh=77.616π
therefore h=17.6cm
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