From each of the two opposite corners of a square of side 8 cm, a quadrant of a circle of radius 1.4 cm is cut. Another circle of radius 4.2 cm is also cut from the centre as shown in fig. Find the area of the shaded portion. (Useπ = 227).
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SOLUTION:
GIVEN:
Side of a square = 8 cm
Radius of a quadrant = 1. 4 cm
Radius of a circle = 4.2 cm
Area of a square = side²
AREA OF A SQUARE = 8² = 64 cm²
Area of quadrant = ¼ πr²
AREA OF 2 QUADRANTS = 2 × ¼ πr² = ½ π r²
= ½ × 22/7 × 1.4² = 11× 0.2 × 1.4 = 2.2 × 1.4 = 3.08 cm²
AREA OF CIRCLE = πr² = 22/7 × 4.2² = 22 × 0.6 × 4.2 = 13.2 × 4.2 = 55.44 cm²
Area of shaded region = area of square -(area of 2 quadrants + area of circle)
AREA OF SHADED REGION= 64 -(3.08 + 55.44) = 64 - 58.52 = 5.48 cm²
AREA OF SHADED REGION= 5.48 cm²
Hence, the area of shaded region is 5.48 cm².
HOPE THIS WILL HELP YOU...
GIVEN:
Side of a square = 8 cm
Radius of a quadrant = 1. 4 cm
Radius of a circle = 4.2 cm
Area of a square = side²
AREA OF A SQUARE = 8² = 64 cm²
Area of quadrant = ¼ πr²
AREA OF 2 QUADRANTS = 2 × ¼ πr² = ½ π r²
= ½ × 22/7 × 1.4² = 11× 0.2 × 1.4 = 2.2 × 1.4 = 3.08 cm²
AREA OF CIRCLE = πr² = 22/7 × 4.2² = 22 × 0.6 × 4.2 = 13.2 × 4.2 = 55.44 cm²
Area of shaded region = area of square -(area of 2 quadrants + area of circle)
AREA OF SHADED REGION= 64 -(3.08 + 55.44) = 64 - 58.52 = 5.48 cm²
AREA OF SHADED REGION= 5.48 cm²
Hence, the area of shaded region is 5.48 cm².
HOPE THIS WILL HELP YOU...
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