Math, asked by maahira17, 1 year ago

From each of the two opposite corners of a square of side 8 cm, a quadrant of a circle of radius 1.4 cm is cut. Another circle of radius 4.2 cm is also cut from the centre as shown in fig. Find the area of the shaded portion. (Useπ = 227).

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Answered by nikitasingh79
135
SOLUTION:

GIVEN:
Side of a square = 8 cm
Radius of a quadrant = 1. 4 cm
Radius of a circle = 4.2 cm

Area of a square = side²
AREA OF A SQUARE = 8² = 64 cm²

Area of quadrant = ¼ πr²
AREA OF 2 QUADRANTS = 2 × ¼ πr² = ½ π r²
= ½ × 22/7 × 1.4² = 11× 0.2 × 1.4 = 2.2 × 1.4 = 3.08 cm²

AREA OF CIRCLE = πr² = 22/7 × 4.2² = 22 × 0.6 × 4.2 = 13.2 × 4.2 = 55.44 cm²

Area of shaded region = area of square -(area of 2 quadrants + area of circle)
AREA OF SHADED REGION= 64 -(3.08 + 55.44) = 64 - 58.52 = 5.48 cm²
AREA OF SHADED REGION= 5.48 cm²

Hence, the area of shaded region is 5.48 cm².

HOPE THIS WILL HELP YOU...
Answered by sowmiya35
33
refer to the attachment
:-)
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