Question

From equation , N2 + 3H2 = 2NH3, calculate the volume of ammonia gas formed when 6 litres of hydrogen react with excess nitrogen , all the volumes being measured at STP.

Answer 1

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Answer 2

Answer:

xNH₃ = 4

Explanation:

As per Avogadro's law of gases, equal volumes of different gases contains equal number of molecules, under the same conditions of temperature and pressure.

Given

N2 + 3H2 = 2NH3,

To find

calculate the volume of ammonia gas formed when 6 litres of hydrogen react with excess nitrogen

Solution

From the reaction,

N₂+ 3H₂ = 2NH₃

When one mole of nitrogen reacts with three moles of hydrogen it gives two moles of ammonia.

Number of moles = $\frac{Given volume}{22.4L}$

As, here hydrogen is the limiting reagent and nitrogen is present in excess.

Therefore, when

3H₂ → 2NH₃

Then

6H₂ →xNH₃

xNH₃=  6H₂ x 2NH₃ / 3H₂

xNH₃ = 4

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