Question

from first 20 natural numbers if two numbers are selected at random then the probability of selecting them which are not consecutive years

Answer 1

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$<b>Answer</b>$

P(E) = 0.1

$<b>Step-by-step explanation</b>$

P(E) = $\frac{No. of outcomes}{total number of outcomes}$

P(E) = $\frac{2}{20}$

P(E) = $\frac{1}{10}$

P(E) = 0.1


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Answer 2

P(E) =0.1

Thanks....!