From how much height should we let the ball shown in figure roll - down the incline on the left hand side, so that it looks the loop and the rolls-up the incline on the other side
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Answered by
1
To just complete the track potential energy at height h
(Point P)=(Kinetic+ potential) energy at H
mgh=2mgR+
2
1
mv
0
2
+
2
1
Iω
0
2
where v
0
is velocity required to complete the loop
R
mv
0
2
=mg⇒v
0
2
=gR
mgh=2mgR+
2
1
mv
0
2
+
2
1
×
5
2
mr
2
×
R
v
0
2
gh=2gR+
2
1
gR+
5
1
R
2
r
2
.gR (ω
0
=
R
v
0
pure rolling)
h=
2
5R
+
5
R
[
R
2
r
2
]
Answered by
0
Answer:
From how much height should we let the ball shown in figure roll - down the incline on the left hand side, so that it looks the loop and the rolls-up the incline on the other side
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