from point P,5cm away from the centre of a circle,a tangent of a length 4cm is drawn.then the radius of the circle is
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Solution is given below ...................
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given C(O,r) PO=5cm PA=4cm
To find OA
Sol Angles between radius and tangent of circle is right angle
angle PAO=90
in rt Δ
![{po }^{2} = {oa}^{2} + {pa}^{2} \\ {5}^{2} = {oa}^{2} + {4}^{2} \\ \sqrt{25 - 16} = oa \\ \sqrt{9} = oa \\ 3 = oa \\ hope \: it \: help \: you \: and \: you \: mark \: it \: as \: a \: brainlist \: answer {po }^{2} = {oa}^{2} + {pa}^{2} \\ {5}^{2} = {oa}^{2} + {4}^{2} \\ \sqrt{25 - 16} = oa \\ \sqrt{9} = oa \\ 3 = oa \\ hope \: it \: help \: you \: and \: you \: mark \: it \: as \: a \: brainlist \: answer](https://tex.z-dn.net/?f=++%7Bpo+%7D%5E%7B2%7D++%3D++%7Boa%7D%5E%7B2%7D+++%2B++%7Bpa%7D%5E%7B2%7D+%5C%5C++%7B5%7D%5E%7B2%7D++%3D++%7Boa%7D%5E%7B2%7D++%2B+++%7B4%7D%5E%7B2%7D++%5C%5C+%5Csqrt%7B25+-+16%7D+++%3D++oa+%5C%5C++%5Csqrt%7B9%7D+%3D+oa+%5C%5C+3+%3D+oa+%5C%5C+hope+%5C%3A+it+%5C%3A+help+%5C%3A+you+%5C%3A+and+%5C%3A+you+%5C%3A+mark+%5C%3A+it+%5C%3A+as+%5C%3A+a+%5C%3A+brainlist+%5C%3A+answer)
To find OA
Sol Angles between radius and tangent of circle is right angle
angle PAO=90
in rt Δ
Attachments:
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