From point Q the length of tangent to circle is 24 cm and the distance Q from the centre is 25 cm then the area of the circle is:
A. 7 pi
B. 14 pi
C. 49 pi
D. None of these
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Let the point of tangency (The point where the tangent and radius meets in a circle) be P and the centre be O.
According to question:
- Length of PQ = 24 cm
- Length of OQ = 25 cm
We know, the tangent is perpendicular to the radius of the circle at the point of tangency. So, ∆OPQ is a right-angled triangle.
By using Pythagoras theoram,
⇛ OP² + PQ² = OQ²
⇛ OP = √OQ² - PQ²
⇛ OP = √25² - 24²
⇛ OP = √49 cm
⇛ OP = 7 cm
Radius of the circle is 7 cm. Now we can find the area of the circle by using formula,
⇛ Area = πr²
⇛ Area = 7² × π
⇛ Area = 49π
The options are in the form of π, hence the correct answer is Option C. And we are done....
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