From rifle of mass 4kg , a bullet of mass 50g is fired with an initial velocity of 35m/s . Calculate the initial recoil velocity of the rifle
Answers
Answer:
Given,
Mass of bullet (m1): 50g =0.05 kg
Mass of rifle(m2):. Initial velocities of the bullet(u1) and rifle(u2)=0
Final velocity of bullet: 35m/s. Let (v) be the recoil velocity of the Rifle
Explanation:
Total momentum of the Rifle and the bullet before the fire, when the Rifle is at rest
=( 4+0.05)kg × 0 m/s
=0 kg m/s
Total momentum of the Rifle and the bullet after it is fired = 0.05 kg × ( 35m/s)+4 kg × v m/s
= (1.75 + 4 v) kg m/s
According to the law of conservation of momentum
Total moments after the fire = Total momenta before fire
1.75 + 4 v = 0
= v = - 0.4375
Negative sign indicates that the direction in which the Rifle would recoil is opposite to that of bullet.
Answer:
Given,
Mass of bullet (m1): 50g =0.05 kg
Mass of rifle(m2):. Initial velocities of the bullet(u1) and rifle(u2)=0
Final velocity of bullet: 35m/s. Let (v) be the recoil velocity of the Rifle
Explanation:
Total momentum of the Rifle and the bullet before the fire, when the Rifle is at rest
=( 4+0.05)kg × 0 m/s
=0 kg m/s
Total momentum of the Rifle and the bullet after it is fired = 0.05 kg × ( 35m/s)+4 kg × v m/s
= (1.75 + 4 v) kg m/s
According to the law of conservation of momentum
Total moments after the fire = Total momenta before fire
1.75 + 4 v = 0
= v = - 0.4375
Negative sign indicates that the direction in which the Rifle would recoil is opposite to that of bullet.
Explanation: