Question

From sea level, a submarine descends 40 feet per minute. Where is the submarine in relation to sea level 5 minutes after it starts descending?

Answer 1

Step-by-step explanation:

formula for distance traveled (in this case the distance a submarine descends) over a period of time is:

d=r⋅t where d is the distance traveled (or descended), r is the rate of travel and t is the time.

In this problem we are told the rate, r is 75 feet per minute. And, we are told the time, t, to calculate for which is 12 minutes.

Substituting these into the formula and calculating gives:

d=75feetmin⋅12min

d=75feetmin⋅12min

d=75feet⋅12

d=900feet

Answer 2

Answer:

900

Step-by-step explanation:

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