From solid, cylinder whose height is 15em and
the diameter is 16cm, a conical cavity of
the same height and same diameter is hollowed
out. Find the total surface area of remaining
solid.
Answers
Answered by
34
solid cylinder, whose height is 15 cm.
the diameter is = 16 cm.
a conical cavity of same height and same
diameter is hollow out.
Height of cylinder = Height of cone = 15 cm.
Radius of the cylinder = Radius of the cone
=> 8 cm .
slant height of the cone.
Total surface area of the remaining solid.
=> C.S.A of cone + C.S.A of cylinder +
=> area of the base
Answered by
59
Answer:
⭐ Question⭐
✏ From solid, cylinder whose height is 15em and the diameter is 16cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of remaining solid.
⭐ Given ⭐
✏ Solid cylinder, whose height is 15 cm.
✏ Diameter is = 16 cm.
✏ A conical cavity of same height and same diameter is hollow out.
⭐ To Find ⭐
✏ T.s.a of remaining solid.
⭐ Solution ⭐
✏ Height of cylinder = Height of cone = 15 cm.
✏Radius of the cylinder = Radius of the cone = 8 cm .
✏ Slant height of the cone.
=> l= √h²+r²
=> l= √(15)² +(8)²
=> l= √225+64
=> l= √289
=> l=17cm
✏Total surface area of the remaining solid.
Total surface area of the remaining solid.
=> C.S.A of cone + C.S.A of cylinder +Total surface area of the remaining solid.
=> C.S.A of cone + C.S.A of cylinder +=> area of the base
=>πrl+2πrh+πr²
=>πr(l+2h+r)
=>3.14×8(17+2×15+8)
=>1381.6cm²
Step-by-step explanation:
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