Math, asked by bhavitasagi, 7 months ago

from stock of 120 kg of wheat, Ratan sells potions weighing 27 kg 31 1/4 kg and 47 3/4 kg how many kg of wheat did he sell ?

Answers

Answered by Anonymous
0

Answer:

Total CP of Rice =200×1.25= Rs. 250

Total CP of Wheat =400×0.75= Rs. 300

Total CP of Jawar =300×0.5= Rs. 150

Total cost =250+300+150= Rs. 700

CP +25% profit =700+25% of 700= Rs. 875

He sells 100 kg rice at 25% loss.

SP of 100 kg rice =125−25% of 125=125−

100

25

×125=93.75.

SP of 100 kg wheat=75+25% of 75=75+

100

25

×75=93.75.

SP of 100 kg Jawar =50+30% of 50=50+

100

30

×50=65.

Now, he mixes, 100 kg rice, 300 kg wheat and 200 kg jawar ,

Total mixture = 100+300+200=600kg

He sells

3

1

mixture i.e. 200 kg of mixture at price 1 rupee per kg.

So, SP =200

Remaining Mixture =400 kg

Till now SP=93.75+93.75+65+200=Rs.452.5

Now, he needs, 875−452.5=Rs.422.5 to get 25% profit.

So, selling price of remaining mixture =

400

422.5

= Rs. 1.06.

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