Question

From the adjoining diagram ,calculate
i)the area of Trapezium ACDE
ii)The area of parallelogram ABDE
iii)The area of triangle BCD​

Answer 1

Answer:

i) 65 m^2 ii) 45.5 m^2 iii) 19.5 m^2

Step-by-step explanation:

i) area of trapezium=1/2(sum of parallel side)*height

i.e a=1/2(7+13)(6.5)

=> a= 65 m^2

ii) area of parallelogram= base*height

i.e a= 7*6.5

=> a= 45.5 m^2

iii) area of triangle=1/2(base)*(height)

i.e a=1/2(13-7)(6.5)

=> a= 19.5 m^2

Answer 2

$\bold {\huge {Solution-:}}$


$\bold {\underline {1.\ The\ area\ of\ trapezium\ ACDE}}$

$\bold {Given}$ $\implies$ Height = 6.5m and sum of parallel sides = 13m and 7m

$\bold {To\ Find}$$\implies$ Area of trapezium ACDE

$\implies$Area of trapezium = $\dfrac {1}{2}$ × (sum of parallel sides) × height

$\implies$Area of trapezium of ACDE = $\dfrac {1}{2}$ × (13 + 7) × 6.5

$\implies$ $\dfrac {1}{2}$ × 20 × 6.5

$\implies$ 10 × 6.5

$\implies$ 65m^2

$\boxed {\bold {Area\ of\ trapezium\ =\ 65m^2}}$


$\bold {\underline {2.\ The\ area\ of\ parallelogram\ ABDE}}$

$\bold {Given}$ $\implies$ height = 6.5m and base = 7m

$\bold {To\ Find}$$\implies$ Area of parallelogram ABDE

$\implies$Area of parallelogram = base × height

$\implies$Area of parallelogram = 6.5 × 7

$\boxed {\bold {Area\ of\ parallelogram\ =\ 45.5m^2}}$


$\bold {\underline {3.\ The\ area\ of\ triangle\ BCD}}$

$\bold {Given}$ $\implies$ Height = 6.5m and base = 6m

$\bold {To\ Find}$$\implies$ Area of triangle BCD

$\implies$Area of triangle = $\dfrac {1}{2}$ × base × height

$\implies$ $\dfrac {1}{2}$ × 6 × 6.5

$\implies$ 3 × 6.5

$\boxed {\bold {Area\ of\ triangle\ =\ 19.5m^2}}$


$\bold {\huge {Solved}}$