Question

if two charges +9electron and-4electron are placed at a 15cm apart.at which line joining the charges and another charge q0 should be placed so that the charges q0 remain in equilibrium​

Answer 1

1/4π€0*q1q2q0/r3

=9*10^9*(36)/(15*10^-2)^3*q

q0=2.6669