From the adjoining figure, find
(i) sin x
(ii) cos y.
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3
Answer:
sin x = 4/5
cos y = 12/13
Explanation:
solved in attachment
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Sin x = 4/5
Cosy = 12/13
Explanation:
(i) Triangle BCD is a right-angled triangle with BC = 4 and CD = 3.
So BD^2 = BC^2 + CD^2
BD = root of (BC^2 + CD^2) = root of (3^2 + 4^2) = root of 25 = 5.
Sin x = BC / BD = 4 / 5
(ii) Triangle ABD is a right-angled triangle with AB = 12.
BD derived above as 5.
So AD^2 = AB^2 + BD^2
AD = root of (AB^2 + BD^2) = root of (12^2 + 5^2) = root of 169 = 13.
Cos y = BA / AD = 12 / 13
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