Question

Write the equation given below in its ionic form
CuSO₄ (aq) + Fe (s) → FeSO₄ (aq) + Cu (s)

Answer 1

Equation in ionic form is written below-

Cu(2+) SO4(2-) + Fe --> Cu + Fe(2+) SO4(2-)

•Copper, iron and sulphate ions are present in given reaction.

•Copper and iron are positively charged ions.

•They have two less electrons in their octet, which makes them reactive.

•They gain electron, and hence are reduced.

•Sulphate molecule has two extra electron, which donates electron to electron deficient species.

•Thus it gets oxidized.

Answer 2

The ionic form of given equation is as follow:--

(Cu)^+2 + (SO4)^-2 + Fe------->(Fe)^+2 + (SO4)^-2 + Cu

• The above equation is an example of displacement reaction in which iron displaces copper from its solution.
• The reactants for reaction are copper sulphate solution reacting with elemental iron, so the ions on reactant side are copper ions with +2 oxidation state, sulphate ions with-2 oxidation state and elemental iron.
• The products of reaction are ferrous sulphate solution and elemental copper, so the ions on product side are ferrous ion with +2 oxidation state , sulphate ions with -2 oxidation state and elemental copper.