Math, asked by tris09038a, 9 months ago

From the adjoining figure, find i. x ii. ∠DAB iii. ∠ADB

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Answers

Answered by nalanagulajagadeesh

6

Answer:

1)from ∆DAB,

3x+10+3x+4+50=180°,

=>6x+64=180°,

=>6x=116°,

=>x=19.33°.

2)<DAB=3x+4=62°.

3)<ADB=3x+10=68°

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