From the equation {{(N{{H}_{4}})}_{2}}C{{r}_{2}}{{O}_{7}}\to C{{r}_{2}}{{O}_{3}}+4{{H}_{2}}O+{{N}_{2}}(NH 4 ) 2 Cr 2 O 7 →Cr 2 O 3 +4H 2 O+N 2 , calculate the mass of chromium(III) oxide C{{r}_{2}}{{O}_{3}}Cr 2 O 3 formed when 63g of ammonium dichromate is heated (N=14u, H=1u, Cr=52u, O=16u).
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Answer:
2H
2
S(g)⇌2H
2
(g)+S
2
(g)
At 1mol 0.2 0.8
eqb
conc 1/2 0.2/2 0.8/2
=0.1 =0.4
K
C
=
(0.5)
2
(0.1)
2
×(0.4)
⇒4×0.4×10
−2
⇒0.016
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