Question

from the following equation, A2+B2 gives 2AB ; delta H =+48 k.cal. Heat of formation of AB is​

Answer 1

Answer:

20 Kg/J

Explanation:

ΔH  

1

​  

=ΔG  

o

+TΔS  

o

=20+200(−20)=−3980KJ

ΔH  

o

=ΔE+C  

p

​  

ΔT

ΔE=ΔH  

1

​  

 

ΔH  

o

=−3980+20(400−200)=−3980+4000=20kJ/mole