Math, asked by niharikabesi, 8 months ago

from the following pattern find the missing numbers
 {1 }^{2}  +  {2}^{2}  +  {2}^{2}  =  {3}^{2}
 {2}^{2}  +  {3}^{2}  +  {6}^{2}  =  {7}^{2}
 {3}^{2}  +   {4}^{2}  +  {12}^{2}  =  {13}^{2}
 {4}^{2}  +  {5}^{2}  +  {?}^{2}  =  {21}^{2}
 {5}^{2}  +  {?}^{2}  +  {30}^{2}  =  {?}^{2}
 {6}^{2}  +  {7}^{2}  +  {?}^{2}  =  {?}^{2}


Answers

Answered by rupeshkumartandan93
1

Answer:

 {4}^{2}  +  {5}^{2}  +  {20}^{2}  =  {21}^{2}   \\  {6}^{2}  +  {7}^{2}  +  {42}^{2}  =  {43}^{2}

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